cza wolnym od uszkodzeń z rozkładu Weibulla metodą najmniejszych kwadratów (M

14:44 Dec 29, 2010
This question was closed without grading. Reason: Errant question

Polish to English translations [PRO]
Social Sciences - Mathematics & Statistics
Polish term or phrase: cza wolnym od uszkodzeń z rozkładu Weibulla metodą najmniejszych kwadratów (M
W niniejszym artykule, przedstawiono oszacowanie parametru zwanego czasem wolnym od uszkodzeń z rozkładu Weibulla metodą najmniejszych kwadratów (MNK).
lucypl
Poland
Local time: 19:05


Summary of answers provided
3time to failure
M.A.B.
3 -1inapplicable
Paul Merriam


Discussion entries: 3





  

Answers


17 mins   confidence: Answerer confidence 3/5Answerer confidence 3/5 peer agreement (net): -1
inapplicable


Explanation:
This doesn't really lend itself to a translation of the term indicated. (To start with, you left off the "sem" on czasem and the NK in MNK.) The article provides an estimate of the parameter called "czas wolny" (free time) as a function of Weibull-distributed error (uszkodzeń z rozkładu Weibulla) using the least squares method (metodą najmniejszych kwadratów).

Paul Merriam
Local time: 13:05
Works in field
Native speaker of: English
PRO pts in category: 4

Peer comments on this answer (and responses from the answerer)
disagree  M.A.B.: What is "uszkodzeń z rozkładu Weibulla"??
7 mins
  -> This is Weibull-distributed error. An assumption was made that the error term in the model had a Weibull distribution.
Login to enter a peer comment (or grade)

3 days 2 hrs   confidence: Answerer confidence 3/5Answerer confidence 3/5
czas wolny od uszkodzeń
time to failure


Explanation:
Zgodnie z zasadami KudoZ, odpowiadam na jeden termin - pierwszy z listy co najmniej trzech.

Pewność średnia, bo nie bardzo wiem w jaki sposób czas wolny od uszkodzeń wiąże się z socjologią - a dodatkowo, ten termin po polsku chyba nie jest poprawny.

Example sentence(s):
  • If the quantity X is a "time-to-failure", the Weibull distribution gives a distribution for which the failure rate is proportional to a power of time. The shape parameter, k, is that power plus one, and so this parameter can be interpreted directly as fol

    Reference: http://en.wikipedia.org/wiki/Weibull_distribution#Definition
    Reference: http://pl.wikipedia.org/wiki/MTTF
M.A.B.
Poland
Local time: 19:05
Specializes in field
Native speaker of: Native in PolishPolish
PRO pts in category: 178
Login to enter a peer comment (or grade)



Login or register (free and only takes a few minutes) to participate in this question.

You will also have access to many other tools and opportunities designed for those who have language-related jobs (or are passionate about them). Participation is free and the site has a strict confidentiality policy.

KudoZ™ translation help

The KudoZ network provides a framework for translators and others to assist each other with translations or explanations of terms and short phrases.


See also:
Term search
  • All of ProZ.com
  • Term search
  • Jobs
  • Forums
  • Multiple search